BPSC 71th Solution

Q. What is the device to protect equipments from the electric shock?

Q. What is the device to protect equipments from the electric shock?

a) Motor
b) Generator
c) Fuse
d) Current controller
Correct Answer : c) Fuse

Question from BPSC PT 71, 2025

Correct Answer: c) Fuse

Explanation:
– A fuse is a safety device connected in series with the circuit.
– If an overload or short circuit occurs, the current rises above a safe level.
– The fuse element heats up and melts (“blows”), opening the circuit and cutting off power.
– This prevents damage to equipment and reduces the risk of electric shock and fire.

Motors and generators are energy-conversion devices, not protective devices. A “current controller” regulates current but does not automatically interrupt dangerous fault currents like a fuse does.

Q. What is the device to protect equipments from the electric shock? Read More »

Q. In short circuit, the value of electric current in a time circuit:

Q. In short circuit, the value of electric current in a time circuit:

a) Increases very high
b) Do not change
c) Very low
d) Continuously changing
Correct Answer : a) Increases very high

Question from BPSC PT 71, 2025

Correct Answer: a) Increases very high

Explanation:
– A short circuit provides a path of (almost) zero resistance.
– By Ohm’s law, I = V/R. As R → 0, the current I becomes extremely large (theoretically infinite).
– In practice, it is limited by the source and wiring impedance, but it is still very high compared to normal operation.

Q. In short circuit, the value of electric current in a time circuit: Read More »

Q. Which term in the following does not denote the electric power in electric circuit?

Q. Which term in the following does not denote the electric power in electric circuit?

a) VI
b) IR^2
c) I^2R
d) V^2/R
Correct Answer : b) IR^2

Question from BPSC PT 71, 2025

Correct Answer: b) IR^2

Explanation:
– Electric power is given by P = VI.
– Using Ohm’s law (V = IR) for a resistive circuit:
– P = VI = (IR)·I = I^2R
– Also, P = VI = V·(V/R) = V^2/R
– Thus, VI, I^2R, and V^2/R are valid power expressions.
– IR^2 = I·R^2 is not a power expression; its units are A·Ω^2 = V^2/A, which are not watts (V·A). Hence, it does not denote electric power.

Q. Which term in the following does not denote the electric power in electric circuit? Read More »

Q. The focal distance of a plane mirror is

Q. The focal distance of a plane mirror is

a) 2 cm
b) -1 cm
c) 1 cm
d) Infinity
Correct Answer : d) Infinity

Question from BPSC PT 71, 2025

Correct Answer: d) Infinity

Explanation:
– For mirrors, focal length f is related to the radius of curvature R by f = R/2.
– A plane mirror can be thought of as a spherical mirror with an infinite radius of curvature (R = ∞).
– Therefore, its focal length is f = ∞/2 = ∞.
– Physically, a plane mirror does not converge or diverge parallel rays; they remain parallel, so the focus is at infinity.

Q. The focal distance of a plane mirror is Read More »

Q. A pair of Oxen exerts a force of 140 newton while ploughing the field. The field ploughed is 15 meter long. The work done in ploughing the length of the field is :

Q. A pair of Oxen exerts a force of 140 newton while ploughing the field. The field ploughed is 15 meter long. The work done in ploughing the length of the field is :


a) 2100 Joule
b) 2000 Joule
c) 1900 Joule
d) 2200 Joule
Correct Answer : a) 2100 Joule

Question from BPSC PT 71, 2025

Correct Answer: a) 2100 Joule

Explanation:
– Work done (W) = Force (F) × Displacement (s) × cos(θ)
– Here, the force is along the direction of motion, so θ = 0° and cos(0°) = 1.
– W = 140 N × 15 m × 1 = 2100 N·m = 2100 J
Hence, the work done is 2100 Joule.

Q. A pair of Oxen exerts a force of 140 newton while ploughing the field. The field ploughed is 15 meter long. The work done in ploughing the length of the field is : Read More »

Q. The potential energy of a freely falling body continuously decreases.

Q. The potential energy of a freely falling body continuously decreases.

a) Gravitational force is violated
b) The principle of conservation of energy is not violated
c) The principle of conservation of energy is violated
d) Gravitational force is not violated
Correct Answer: b) and d)

Question from BPSC PT 71, 2025

Correct Answer: b) and d)

Explanation:
– In free fall (ignoring air resistance), as height decreases, gravitational potential energy U = mgh decreases. The lost potential energy is converted into kinetic energy K = 1/2 mv^2.
– Since ΔK = −ΔU, the total mechanical energy E = K + U remains constant. So the principle of conservation of energy is not violated (option b).
– This behavior is exactly what a conservative gravitational force predicts; there is no “violation” of gravity (option d). Options a and c are false.

Q. The potential energy of a freely falling body continuously decreases. Read More »

Q. In which medium, the speed of sound is maximum?

Q. In which medium, the speed of sound is maximum?

a) Air
b) Water
c) Steel
d) Hydrogen
Correct Answer : c) Steel

Question from BPSC PT 71, 2025

Correct Answer: c) Steel

Explanation:
The speed of sound depends on how stiff (elastic) a medium is and how dense it is. In general:
– Solids > Liquids > Gases for speed of sound.

This is because solids have a much higher elastic modulus compared to their density, allowing sound to travel faster.

Approximate speeds:
– Air: ~343 m/s
– Hydrogen (fastest gas): ~1,300 m/s
– Water: ~1,480 m/s
– Steel: ~5,000–6,000 m/s

Thus, among the options, sound travels fastest in steel.

Q. In which medium, the speed of sound is maximum? Read More »

Q. Energy consumed in a home is 250 units then the total energy in Joule will be:

Q. Energy consumed in a home is 250 units then the total energy in Joule will be:

a) 9×10^8
b) 8×10^6
c) 9×10^5
d) 10^5
Correct Answer : a) 9×10^8

Question from BPSC PT 71, 2025

Correct Answer: a) 9 × 10^8

Explanation:
– 1 “unit” of electrical energy = 1 kWh = 3.6 × 10^6 J
– For 250 units: Energy = 250 × 3.6 × 10^6 J = 900 × 10^6 J = 9 × 10^8 J

Q. Energy consumed in a home is 250 units then the total energy in Joule will be: Read More »

Q. A truck starts from rest down a hill with a constant acceleration. It achieves 400 meters in 20 seconds. If the weight of the truck is 7 tons then what will be the force acting on it?

Q. A truck starts from rest down a hill with a constant acceleration. It achieves 400 meters in 20 seconds. If the weight of the truck is 7 tons then what will be the force acting on it?

a) 13000 Newtons
b) 12000 Newtons
c) 11000 Newtons
d) 14000 Newtons
Correct Answer : d) 14000 Newtons

Question from BPSC PT 71, 2025

Correct Answer: d) 14000 Newtons

Explanation:
– The truck starts from rest and covers s = 400 m in t = 20 s with constant acceleration a.
– Use s = (1/2) a t^2 ⇒ 400 = (1/2) a (20)^2 ⇒ 400 = 200a ⇒ a = 2 m/s^2.
– Mass of the truck: 7 tons = 7000 kg (taking 1 ton = 1000 kg).
– Net force causing the acceleration: F = m a = 7000 × 2 = 14,000 N.

Q. A truck starts from rest down a hill with a constant acceleration. It achieves 400 meters in 20 seconds. If the weight of the truck is 7 tons then what will be the force acting on it? Read More »

Q. We apply a force of 200 Newtons on a wooden Box and push it on the floor at constant velocity. The marginal friction force will be:

Q. We apply a force of 200 Newtons on a wooden Box and push it on the floor at constant velocity. The marginal friction force will be:

a) 300 Newtons
b) 200 Newtons
c) 100 Newtons
d) 400 Newtons
Correct Answer : b) 200 Newtons

Question from BPSC PT 71, 2025

Correct Answer: b) 200 Newtons

Explanation:
– The box is moving at constant velocity, which means its acceleration is zero.
– By Newton’s First Law (or using ΣF = m·a), if acceleration is zero, the net force must be zero.
– Along the direction of motion: Applied force − Friction force = 0 ⇒ Friction force = Applied force.
– Therefore, the kinetic (sliding) friction balances the push: Friction = 200 N, opposite to the motion.

Q. We apply a force of 200 Newtons on a wooden Box and push it on the floor at constant velocity. The marginal friction force will be: Read More »