CSAT 2020

Q. Let p, q, r and s be natural numbers such that p – 2016 = q + 2017 = r-2018 = s + 2019 

Q. Let p, q, r and s be natural numbers such that p – 2016 = q + 2017 = r-2018 = s + 2019

which one of the following is the largest natural number?
(a) P
(b) Q
(c) R
(d) S
Correct Answer: (c) R

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

p-2016=q+2017=r-2018=s+2019

From the given relations, we have p – q = 4033 and r – q = 4035. This implies that r is greater than p and q.

Also, r – s = 4037, which means that r is greater than s.

Thus, we have established that r is the greatest of all the given natural numbers. Therefore, the correct option is (c) R.

Largest Natural Number R

Q. Let p, q, r and s be natural numbers such that p – 2016 = q + 2017 = r-2018 = s + 2019  Read More »

Q. How many zeroes are there at the end of the following product? 

Q. How many zeroes are there at the end of the following product?

1 x 5 x 10 x 15 x 20 x 25 x 30 x 35 x 40 x 45 x 50 x 55 x 60
(a) 10
(b) 12
(c) 14
(d) 15
Correct Answer: (a) 10

Question from UPSC Prelims 2020 CSAT Paper

Explanation : 

Number of zeroes

1 × 5 × 10 × 15 × 20 × 25 × 30 × 35 × 40 × 45 × 50 × 55 × 60
= 1 × 5 × (5 × 2) × (5 × 3) × (5 × 2^2) × (5 × 5) × (5 × 3 × 2) × (5 × 7) × (5 × 2^3) × (5 × 9) × (5 × 5 × 2) × (5 × 11) × (5 × 2^2 × 3)
Here, number of 2s = 10
And number of 5s = 14
The lesser of the two will determine the number of zeros.
Hence, there will be 10 zeros at the end in the given expression.

Number of Zeroes in Product

Q. How many zeroes are there at the end of the following product?  Read More »

Q. Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

Q. Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

(a) 3
(b) 9
(c) 37
(d) (X + Y + Z)

Correct Answer: (b) 9

Question from UPSC Prelims 2020 CSAT Paper

Model Answer:

XYZ be a three-digit number

Let’s write XYZ in expanded form, where X, Y, and Z are the digits in the hundreds, tens, and units places, respectively.

XYZ = 100X + 10Y + Z

Similarly, we can write YZX and ZXY in expanded form:

YZX = 100Y + 10Z + X
ZXY = 100Z + 10X + Y

Adding these three expressions, we get:

XYZ + YZX + ZXY = 100X + 10Y + Z + 100Y + 10Z + X + 100Z + 10X + Y
= 111X + 111Y + 111Z=111(X + Y + Z)

Factors of 111 are 3 and 37. That eliminate option 3 and 37.

Addition of Expanded Forms

Q. Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by Read More »

Q. If you have two straight sticks of length 7.5 feet and 3.25 feet, what is the minimum length can you measure?

Q. If you have two straight sticks of length 7.5 feet and 3.25 feet, what is the minimum length can you measure?

(a) 0.05 foot

(b) 0.25 foot

(c) 1 foot

(d) 3.25 feet

Correct Answer – (b) 0.25 foot.

Question from UPSC Prelims 2020 CSAT Paper

Model Answer:

2 Straight Sticks Length of 7.5 & 3.25 Feet

To find the minimum length that can be measured using two straight sticks of length 7.5 feet and 3.25 feet using the Highest Common Factor (HCF) method, we can first convert the lengths to inches:

7.5 feet = 90 inches
3.25 feet = 39 inches

Then, we can find the HCF of 90 and 39:

90 = 2 * 3 * 3 * 5
39 = 3 * 13

The common factor is 3, so the HCF is 3 inches.

Two Straight Sticks 7.5 & 3.25 Feet

Therefore, the minimum length that can be measured with these two sticks is 3 inches, which is equivalent to 0.25 feet.

Hence, the correct answer is (b) 0.25 foot.

Q. If you have two straight sticks of length 7.5 feet and 3.25 feet, what is the minimum length can you measure? Read More »