Q. A bus covers the first half of a certain distance with speed v₁ and the second half with a speed v₂. What is the average speed during the whole journey?
a) v₁v₂ / v₁ + v₂
b) 2v₁v₂ / v₁ + v₂
c) v₁ + v₂ / 2
d) √v₁v₂
Question from UPPSC Prelims 2024
Correct Answer: b) 2v1v2 / (v1 + v2)
Explanation:
The average speed is defined as the total distance traveled divided by the total time taken.
1. Let the total distance be “D”.
– The first half of the distance is D/2, and the second half is also D/2.
2. Time taken to cover the first half of the distance:
Speed = Distance / Time, so Time = Distance / Speed.
For the first half, the time taken is:
t1 = D/2 / v1 = D / 2v1
3. Time taken to cover the second half of the distance:
Similarly, for the second half, the time taken is:
t2 = D/2 / v2 = D / 2v2
4. Total time for the journey:
The total time is the sum of t1 and t2:
t_total = t1 + t2 = D / 2v1 + D / 2v2
Taking a common denominator:
t_total = D(v2 + v1) / 2v1v2
5. Average speed formula:
The average speed is given by:
Average speed = Total distance / Total time
Substituting the values:
Average speed = D / t_total = D / (D(v1 + v2) / 2v1v2)
Simplify the expression:
Average speed = 2v1v2 / (v1 + v2)
Final Answer: The average speed during the whole journey is: b) 2v1v2 / (v1 + v2)