Q. A sum of Rs. 2,500 is distributed among X, Y and Z in the ratio

Explanation :

Sum of 2500 is distributed

Given Information:
Total Amount = 2500
Shares distribution:
– X gets a/2
– Y gets 3a/4
– Z gets 5a/6

Solution:
1. Total shares = a/2 + 3a/4 + 5a/6
= a(6 + 9 + 10)/12
= 25a/12

2. Since total is 2500:
25a/12 = 2500
a = 1200

3. Individual Shares:
X = a/2 = 1200/2 = 600
Y = 3a/4 = 3(1200)/4 = 900
Z = 5a/6 = 5(1200)/6 = 1000

4. Finding Difference:
Maximum share = 1000 (Z’s share)
Minimum share = 600 (X’s share)
Difference = 1000 – 600 = 400

Therefore, the difference between maximum and minimum share is 400.