CSAT 2025

Q. Let both p and k be prime numbers such that (p² + k) is also a prime number less than 30. What is the number of possible values of k?

(a) 4
(b) 5
(c) 6
(d) 7

UPSC Prelims 2025 CSAT

Explanation : 

We want primes p and k such that
 p² + k is prime and p² + k < 30.

Step 1. Bound p.
Since k ≥ 2,
 p² + 2 < 30 ⇒ p² < 28 ⇒ p ≤ 5.
So p can be 2, 3, or 5.

Step 2. Test each p:

1. p = 2 ⇒ p² = 4.
Check prime k so that 4 + k is prime < 30:

• k = 2 → 4 + 2 = 6 (not prime)
• k = 3 → 4 + 3 = 7 (prime)
• k = 5 → 4 + 5 = 9 (not prime)
• k = 7 → 4 + 7 = 11 (prime)
• k = 11 → 4 + 11 = 15 (not prime)
• k = 13 → 4 + 13 = 17 (prime)
• k = 17 → 4 + 17 = 21 (not prime)
• k = 19 → 4 + 19 = 23 (prime)
• k = 23 → 4 + 23 = 27 (not prime)

Valid k’s here: 3, 7, 13, 19.

2. p = 3 ⇒ p² = 9.
Check k so that 9 + k is prime < 30:

• k = 2 → 9 + 2 = 11 (prime)
• k = 3 → 12 (no), k = 5 → 14 (no), … all larger k either composite or >30.

Valid k: 2.

3. p = 5 ⇒ p² = 25.
Then 25 + k < 30 ⇒ k < 5; only k = 2 or 3:

• k = 2 → 27 (not prime)
• k = 3 → 28 (not prime)

No solutions for p = 5.

Step 3. Collect all distinct k found:

From p = 2: {3, 7, 13, 19}
From p = 3: {2}

Total distinct k’s = {2, 3, 7, 13, 19}, which is 5 values.

Answer: (b) 5.

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