Q. Let p, q, r and s be natural numbers such that p – 2016 = q + 2017 = r-2018 = s + 2019

Explanation :

p-2016=q+2017=r-2018=s+2019

Let’s solve this step by step:

1) From the given equation:
p – 2016 = q + 2017 = r – 2018 = s + 2019

Let this common value be k. Then:

2) The equations can be written as:
p – 2016 = k
q + 2017 = k
r – 2018 = k
s + 2019 = k

3) Solving for each variable:
p = k + 2016
q = k – 2017
r = k + 2018
s = k – 2019

4) Comparing these expressions:
p = k + 2016
q = k – 2017 (less than p)
r = k + 2018 (larger than p)
s = k – 2019 (less than q)

5) Arranging in descending order:
r = k + 2018
p = k + 2016
q = k – 2017
s = k – 2019

For any value of k, r will be the largest as it has the largest constant (2018) being added to k.

Therefore, r is the largest number. The answer is (c) R.