Q. On one side of a 1.01 km long road, 101 plants are planted at equal distance from each other. What is the total distance between 5 consecutive plants?
a. 40 m
b. 40.4 m
c. 50 m
d. 50.5 m
Correct Answer: b. 40.4 m
Question from UPSC Prelims 2022 CSAT Paper
Explanation :
101 plants on a 1.01 km road
Given information:
– Road length: 1.01 km = 1010 meters
– Total plants: 101
– Plants are equally spaced
– First plant at 0 meters
– Last plant at 1010 meters
Solution steps:
1. Find total gaps between plants:
– Total gaps = Total plants – 1
– Total gaps = 101 – 1 = 100 gaps
2. Find distance between consecutive plants:
– Distance = Total length ÷ Number of gaps
– Distance = 1010 ÷ 100 = 10.1 meters
3. Find distance for 5 consecutive plants:
– Number of gaps = Number of plants – 1
– Number of gaps = 5 – 1 = 4 gaps
– Total distance = Distance per gap × Number of gaps
– Total distance = 10.1 × 4 = 40.4 meters
Answer: The distance between 5 consecutive plants is 40.4 meters