Q. Which one of the following will have minimum change in its value if s is added to both numerator and the denominator of the fractions 2/3, 3/4, 4/5 and 5/6?

Explanation : 

Let’s solve this step by step:

PROBLEM: Finding which fraction has minimum change when s is added to both numerator and denominator

ORIGINAL FRACTIONS:
2/3, 3/4, 4/5, 5/6

NEW FRACTIONS AFTER ADDING s:
(2 + s)/(3 + s)
(3 + s)/(4 + s)
(4 + s)/(5 + s)
(5 + s)/(6 + s)

CHANGES IN VALUE:
|2/3 – (2 + s)/(3 + s)|
|3/4 – (3 + s)/(4 + s)|
|4/5 – (4 + s)/(5 + s)|
|5/6 – (5 + s)/(6 + s)|

ANALYSIS:
1. When s becomes very large:
– The numerator terms (2,3,4,5) become negligible
– The denominator terms (3,4,5,6) become negligible
– All fractions approach s/s = 1

2. Original values:
2/3 ≈ 0.667
3/4 = 0.750
4/5 = 0.800
5/6 ≈ 0.833

3. Since all fractions approach 1:
– The fraction closest to 1 will have minimum change
– 5/6 is closest to 1 among all given fractions

CONCLUSION: The fraction 5/6 will have the minimum change in value when s is added to both numerator and denominator.