BPSC Solution

Q. How many bronze medals were won by Bihar players in the 38th National Junior Athletics Championship 2025?

Q. How many bronze medals were won by Bihar players in the 38th National Junior Athletics Championship 2025?

a) 4
b) 5
c) 6
d) More than one of the above
Correct Answer : b) 5

Question from BPSC PT 71, 2025

Correct Answer : 5


Explanation: 
The medal tally includes 1 Gold, 6 Silver, and 5 Bronze medals. This marks Bihar’s best-ever performance in its sports history at the national level.

Q. How many bronze medals were won by Bihar players in the 38th National Junior Athletics Championship 2025? Read More »

Q. RAIN is written in a code as 8$%6 and MORE is mentioned as 7#8@. How will REMAIN be mentioned in code language?

Q. RAIN is written in a code as 8$%6 and MORE is mentioned as 7#8@. How will REMAIN be mentioned in code language?

a) 86@$#7
b) %7@%6#
c) @$86%7
d) 8@7$%6
Correct Answer : d) 8@7$%6

Question from BPSC PT 71, 2025

Correct Answer: d) 8@7$%6

Explanation:
– From RAIN → 8$%6, we get: R→8, A→$, I→%, N→6
– From MORE → 7#8@, we get: M→7, O→#, R→8, E→@

Now encode REMAIN (R E M A I N) using the mappings:
– R → 8
– E → @
– M → 7
– A → $
– I → %
– N → 6

Thus, REMAIN → 8@7$%6.

Q. RAIN is written in a code as 8$%6 and MORE is mentioned as 7#8@. How will REMAIN be mentioned in code language? Read More »

Q. Find the missing number from the given alternatives: 28 20 7, 84 ? 12, 45 25 9

Q. Find the missing number from the given alternatives: 28 20 7, 84 ? 12, 45 25 9

a) 20
b) 35
c) 30
d) 25
Correct Answer : b) 35

Question from BPSC PT 71, 2025

Correct Answer: b) 35

Explanation:
Look for a consistent relation among the three numbers in each group.

Check the first and third groups:
– 28, 20, 7 → 28 × 5 = 140 and 20 × 7 = 140
– 45, 25, 9 → 45 × 5 = 225 and 25 × 9 = 225

So the pattern is: first × 5 = middle × third.

Apply it to the second group:
– 84, ?, 12 → 84 × 5 = ? × 12
– 420 = 12 × ?
– ? = 420 ÷ 12 = 35

Therefore, the missing number is 35.

Q. Find the missing number from the given alternatives: 28 20 7, 84 ? 12, 45 25 9 Read More »

Q. Rahul is 3 times as old as Seema. Laxmi was twice as old as Rahul four years ago. In four year’s time, Rahul will be 31. What are the present ages of Seema and Laxmi?

Q. Rahul is 3 times as old as Seema. Laxmi was twice as old as Rahul four years ago. In four year’s time, Rahul will be 31. What are the present ages of Seema and Laxmi?

a) 9, 45
b) 9, 52
c) 10, 50
d) 9, 50
Correct Answer : d) 9, 50

Question from BPSC PT 71, 2025

Correct Answer: d) 9, 50

Explanation:
– In 4 years, Rahul will be 31 ⇒ Rahul’s present age R = 31 − 4 = 27.
– Rahul is 3 times as old as Seema ⇒ R = 3S ⇒ 27 = 3S ⇒ Seema’s present age S = 9.
– Four years ago, Rahul was 27 − 4 = 23. Laxmi was twice Rahul’s age then:
L − 4 = 2 × 23 = 46 ⇒ L = 50.
– Therefore, Seema is 9 and Laxmi is 50.

Q. Rahul is 3 times as old as Seema. Laxmi was twice as old as Rahul four years ago. In four year’s time, Rahul will be 31. What are the present ages of Seema and Laxmi? Read More »

Q. If + means x, x means -, ÷ means + and – means ÷, then 175 – 25 ÷ 5 + 20 x 3 + 10 equals to:

Q. If + means x, x means -, ÷ means + and – means ÷, then 175 – 25 ÷ 5 + 20 x 3 + 10 equals to:

a) 140
b) 87
c) 77
d) 70 
Correct Answer : c) 77

Question from BPSC PT 71, 2025

Correct Answer: c) 77

Explanation:
– Replace each symbol by its given meaning:
+ means ×, x means −, ÷ means +, and − means ÷.
– So, 175 – 25 ÷ 5 + 20 x 3 + 10 becomes:
175 ÷ 25 + 5 × 20 − 3 × 10
– Apply BODMAS/PEMDAS:
175 ÷ 25 = 7
5 × 20 = 100
3 × 10 = 30
– Now compute: 7 + 100 − 30 = 77

Therefore, the value is 77.

Q. If + means x, x means -, ÷ means + and – means ÷, then 175 – 25 ÷ 5 + 20 x 3 + 10 equals to: Read More »

Q. Nitin is 7 ranks ahead of Joginder in a class of 39. If Joginder’s rank is 17th from the last, what is Nitin’s rank from the beginning?

Q. Nitin is 7 ranks ahead of Joginder in a class of 39. If Joginder’s rank is 17th from the last, what is Nitin’s rank from the beginning?

a) 18th
b) 15th
c) 17th
d) 16th
Correct Answer : d) 16th

Question from BPSC PT 71, 2025

Correct Answer: d) 16th

Explanation:
– Total students = 39.
– Joginder is 17th from the last, so his rank from the beginning = 39 − 17 + 1 = 23rd.
– Nitin is 7 ranks ahead of Joginder, so Nitin’s rank = 23 − 7 = 16th.

Q. Nitin is 7 ranks ahead of Joginder in a class of 39. If Joginder’s rank is 17th from the last, what is Nitin’s rank from the beginning? Read More »

Q. Writing in Alphabetical order, which name of the following will appear in the last?

Q. Writing in Alphabetical order, which name of the following will appear in the last?

a) Mohender
b) Mohinder
c) Mahinder
d) Mahendra
Correct Answer: b) Mohinder

Question from BPSC PT 71, 2025

Correct Answer: b) Mohinder

Explanation:
– Compare second letters: Names starting with “Mo…” come after those starting with “Ma…” (since o > a).
– So the last name must be one of: Mohender (a) or Mohinder (b).
– Compare “Mohender” vs “Mohinder”: after “Moh”, the next letter is e vs i; since i > e, “Mohinder” comes later.

Thus, the alphabetical order is: Mahendra < Mahinder < Mohender < Mohinder, so the last is “Mohinder” (b).

Q. Writing in Alphabetical order, which name of the following will appear in the last? Read More »

Q. Ram goes North, turn right, then goes right again and then goes to left. In which direction Ram is now?

Q. Ram goes North, turn right, then goes right again and then goes to left. In which direction Ram is now?

a) NORTH
b) SOUTH
c) EAST
d) WEST
Correct Answer : c) EAST

Question from BPSC PT 71, 2025

Correct Answer: c) EAST

Explanation:
– Start facing North.
– Turn right from North → facing East.
– Turn right again from East → facing South.
– Turn left from South → facing East.

So, Ram is now facing East.

Q. Ram goes North, turn right, then goes right again and then goes to left. In which direction Ram is now? Read More »

Q. Mukesh said to his friend, “Rita is the mother of my son’s wife’s daughter”. How is Mukesh related to Rita?

Q. Mukesh said to his friend, “Rita is the mother of my son’s wife’s daughter”. How is Mukesh related to Rita?

a) Son
b) Son-in-law
c) Father
d) Father-in-law 
Correct Answer : d) Father-in-law

Question from BPSC PT 71, 2025

Correct Answer: d) Father-in-law

Explanation:
– “My son” → Mukesh’s son.
– “My son’s wife” → Mukesh’s daughter-in-law.
– “My son’s wife’s daughter” → This girl’s mother is the son’s wife.
– Rita is said to be the mother of that girl, so Rita = Mukesh’s son’s wife (his daughter-in-law).
– Therefore, Mukesh is related to Rita as her father-in-law.

Q. Mukesh said to his friend, “Rita is the mother of my son’s wife’s daughter”. How is Mukesh related to Rita? Read More »

Q. SPRING is written in a code as UNUFRC. How will the word MOBILE be mentioned in that code language?

Q. SPRING is written in a code as UNUFRC. How will the word MOBILE be mentioned in that code language?

a) MPQSUL
b) OMPGNC
c) OMEFPA
d) SEGRFT
Correct Answer : c) OMEFPA

Question from BPSC PT 71, 2025

Correct Answer: c) OMEFPA

Explanation:
Observe the pattern from SPRING → UNUFRC by using alphabet positions (A=1, B=2, …, Z=26):
– S(19) → U(21): +2
– P(16) → N(14): −2
– R(18) → U(21): +3
– I(9) → F(6): −3
– N(14) → R(18): +4
– G(7) → C(3): −4

So the rule is: alternately add and subtract, increasing the step each time: +2, −2, +3, −3, +4, −4.

Apply the same to MOBILE:
– M(13) +2 → O(15)
– O(15) −2 → M(13)
– B(2) +3 → E(5)
– I(9) −3 → F(6)
– L(12) +4 → P(16)
– E(5) −4 → A(1)

Thus, MOBILE → OMEFPA.

Q. SPRING is written in a code as UNUFRC. How will the word MOBILE be mentioned in that code language? Read More »