Prelims Solution

Q. The difference between a 2-digit number and the number obtained by interchanging the positions of the digits is 54.

Q. The difference between a 2-digit number and the number obtained by interchanging the positions of the digits is 54.

1. The sum of the two digits of a number can be determined only if the product of the two digits is known.
2. The difference between the two digits of the number can be determined.

Which of the above statements is/are correct?
(a) 1 only
(b) 2 only
(c) Both 1 and 2
(d) Neither 1 nor 2
Correct Answer: (b) 2 only

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

The difference between 2 digit number and the number obtained is 54

Given:
– Original number = 10x + y (where x is tens digit, y is units digit)
– New number after interchanging = 10y + x
– Difference between these numbers = 54

Step 1: Write equation for the difference
(10x + y) – (10y + x) = 54

Step 2: Simplify left side
10x + y – 10y – x = 54
9x – 9y = 54

Step 3: Further simplify
9(x – y) = 54
x – y = 6

Step 4: Analyze what we know
– Difference between tens and units digit is 6
– Since it’s a 2-digit number:
* x must be from 1 to 9
* y must be from 0 to 9
* x must be greater than y by 6

Step 5: Find possible digit pairs
Since x – y = 6:
– If y = 0, x = 6
– If y = 1, x = 7
– If y = 2, x = 8
– If y = 3, x = 9

Analysis:

1. Statement 1 (about sum of digits) is incorrect
– Multiple pairs of digits satisfy x – y = 6
– Each pair would give different sums
– Examples: 6+0=6, 7+1=8, 8+2=10, 9+3=12

2. Statement 2 (about difference of digits) is correct
– We proved x – y = 6
– This is a definite value

Answer: Statement 1 is incorrect and Statement 2 is correct.

Interchanging 2 Digit Number

Q. The difference between a 2-digit number and the number obtained by interchanging the positions of the digits is 54. Read More »

Q. A pie diagram shows the percentage distribution of proteins, water and on the dry elements in the human body.

Q. A pie diagram shows the percentage distribution of proteins, water and on the dry elements in the human body.

Given that proteins correspond to 16% and water corresponds to 70%. If both proteins and the other dry elements correspond to p%, then what is the central angle of the sector representing p on the pie diagram?

(a) 54°
(b) 96°
(c) 108°
(d) 120°
Correct Answer: (c) 108°

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Pie Chart Analysis

A pie chart represents 100% of the data as a full circle with 360 degrees. In this case, proteins correspond to 16% and water corresponds to 70%, so the other dry elements correspond to 100% – 16% – 70% = 14%. Since p represents the sum of proteins and other dry elements, p = 16% + 14% = 30%.

Since p represents 30% of the data, the central angle of the sector representing p on the pie diagram is (30/100) * 360 = 108 degrees.

Pie Chart - Protein and Dry Elements

Q. A pie diagram shows the percentage distribution of proteins, water and on the dry elements in the human body. Read More »

Q. A biology class at high school predicted that a local population of animals will double in size every 12 years.

Q. A biology class at high school predicted that a local population of animals will double in size every 12 years.

The population at the beginning of the year 2021 was estimated to be 50 animals. If P represents the population after n years, then which one of the following equations represents the model of the class for the population?
(a) P = 12 + 50n
(b) P = 50 + 12n
(c) P = 50(2)^12n
(d) P = 50 (2)^(n/12)
Correct Answer: (d) P = 50 (2)^(n/12)

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Biology Class at High School Population Growth Model

Given:
– Initial population (2021) = 50 animals
– Population doubles every 12 years
– Need formula for population P after n years

Step 1: Identify Growth Type
– Not linear growth (population doesn’t increase by fixed amount)
– Population multiplies by 2 at fixed intervals
– This indicates exponential growth

Step 2: Basic Exponential Growth Formula
P = Initial Value × (growth factor)^(time/interval)

Step 3: Identify Components
– Initial Value = 50
– Growth factor = 2 (doubles)
– Time = n years
– Interval = 12 years

Step 4: Analyze Options
a) P = 12 + 50n
Incorrect: Shows linear growth

b) P = 50 + 12n
Incorrect: Shows linear growth

c) P = 50(2)^12n
Incorrect: Time interval ratio is wrong

d) P = 50(2)^(n/12)
Correct: Shows proper exponential growth

Step 5: Verify Option D
After 0 years: P = 50(2)^0 = 50 (correct initial population)
After 12 years: P = 50(2)^1 = 100 (population doubles)
After 24 years: P = 50(2)^2 = 200 (doubles again)

Answer: The correct formula is P = 50(2)^(n/12)
This formula accurately represents population doubling every 12 years from an initial value of 50 animals.

Q. A biology class at high school predicted that a local population of animals will double in size every 12 years. Read More »

Q. From January 1, 2021, the price of petrol (in Rupees per litre) on mth day of the year is 80 + 0.1m, where m = 1, 2, 3, …, 100 and thereafter remains constant. On the other hand, the price of diesel (in Rupees per litre) on nth day of 2021 is 69 + 0.15n for any n. On which date in the year 2021 are the prices of these two fuels equal?

Q. From January 1, 2021, the price of petrol (in Rupees per litre) on mth day of the year is 80 + 0.1m, where m = 1, 2, 3, …, 100 and thereafter remains constant. On the other hand, the price of diesel (in Rupees per litre) on nth day of 2021 is 69 + 0.15n for any n. On which date in the year 2021 are the prices of these two fuels equal?

(a) 21st May
(b) 20th May
(c) 19th May
(d) 18th May
Correct Answer: (b) 20th May

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Problem: Finding when petrol and diesel prices are equal ?

Given:
– 2021 is non leap year
– Petrol price formula: 80 + 0.1m (where m = 1 to 100, constant thereafter)
– Diesel price formula: 69 + 0.15n (for any value of n)

Step 1: Set up equation for equal prices
80 + 0.1m = 69 + 0.15n

Step 2: Solve for n in terms of m
80 + 0.1m = 69 + 0.15n
0.1m – 0.15n = -11
-0.15n = -11 – 0.1m
n = (2m + 220)/3

Step 3: Find n when m = 100
n = (2(100) + 220)/3
n = (200 + 220)/3
n = 420/3
n = 140

Answer: The prices of petrol and diesel are equal on the 140th day of 2021, which is May 20th.

Petrol and Diesel Price Equality Analysis

Q. From January 1, 2021, the price of petrol (in Rupees per litre) on mth day of the year is 80 + 0.1m, where m = 1, 2, 3, …, 100 and thereafter remains constant. On the other hand, the price of diesel (in Rupees per litre) on nth day of 2021 is 69 + 0.15n for any n. On which date in the year 2021 are the prices of these two fuels equal? Read More »

Q. The number 3798125P369 is divisible by 7. What is the value of the digit P?

Q. The number 3798125P369 is divisible by 7. What is the value of the digit P?

(a) 1
(b) 6
(c) 7
(d) 9
Correct Answer: (b) 6

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Problem: Find the digit P in 3798125P369 so that the number is divisible by 7

Step 1: Divide into Three-Digit Blocks (from right to left)
– Write as: 037, 981, 25P, 369
– This splits the number into blocks of three: 037|981|25P|369

Step 2: Apply Alternating Addition and Subtraction Rule
– Start from rightmost block: 369
– Then alternate: 369 – 25P + 981 – 037
– Note: This is based on the divisibility rule of 7 where we alternate adding and subtracting blocks of 3 digits

Step 3: Simplify the Expression
369 – (250 + P) + 981 – 37
= 369 – 250 – P + 981 – 37
= 1063 – P

Step 4: Solve for P Using Modulo 7
– For the number to be divisible by 7:
– 1063 – P must be divisible by 7
– 1063 ÷ 7 = 151 remainder 6
– So, 1063 ≡ 6 (mod 7)
– Therefore: 6 – P ≡ 0 (mod 7)
– This means P = 6

Answer: P = 6

Q. The number 3798125P369 is divisible by 7. What is the value of the digit P? Read More »

Q. If 3^2019 is divided by 10, then what is the remainder?

Q. If 3^2019 is divided by 10, then what is the remainder?

(a) 1
(b) 3
(c) 7
(d) 9
Correct Answer: (c) 7

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Problem: Find the remainder when 3^2019 is divided by 10

Let’s solve this step by step:

1) To find 3^2019 mod 10, examine the pattern of remainders when successive powers of 3 are divided by 10:
3^1 = 3
3^2 = 9
3^3 = 27 ≡ 7 (mod 10)
3^4 = 81 ≡ 1 (mod 10)
3^5 = 243 ≡ 3 (mod 10)
3^6 = 729 ≡ 9 (mod 10)
3^7 ≡ 7 (mod 10)
3^8 ≡ 1 (mod 10)

2) The pattern of remainders is: 3, 9, 7, 1, 3, 9, 7, 1, …
This forms a cycle of length 4

3) For 3^2019:
2019 = 504 × 4 + 3
Thus 3^2019 will have the same remainder as 3^3

4) Since 3^3 ≡ 7 (mod 10)

Therefore, when 3^2019 is divided by 10, the remainder is 7.

The answer is (c) 7.

Q. If 3^2019 is divided by 10, then what is the remainder? Read More »

Q. Integers are listed from 700 to 1000. In how many integers is the sum of the digits 10?

Q. Integers are listed from 700 to 1000. In how many integers is the sum of the digits 10?

(a) 6
(b) 7
(c) 8
(d) 9
Correct Answer: (d) 9

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

Integers are listed from 700 to 1000

The sum of the digits of an integer is 10 if the digits add up to 10. For example, the number 703 has a digit sum of 7 + 0 + 3 = 10. We can find all integers between 700 and 1000 that have a digit sum of 10 by listing them out:

703, 712, 721, 730, 802, 811, 820, 901, 910.

There are 9 integers between 700 and 1000 that have a digit sum of 10. So the correct answer is (d) 9.

Digit Sum of Integer is 10

Q. Integers are listed from 700 to 1000. In how many integers is the sum of the digits 10? Read More »

Q. A boy plays with a ball, and he drops if from a height of 1.5 m.

Q. A boy plays with a ball, and he drops if from a height of 1.5 m.

Every time the ball hits the ground, it bounces back to attain a height 4/5th of the previous height. The ball does not bounce further if the previous height is less than 50 cm. What is the number of times the ball hits the ground before the ball stops bouncing?

(a) 4
(b) 5
(c) 6
(d) 7
Correct Answer: (b) 5

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

A boy plays with a ball

Starting height = 1.5 meters
Bounce ratio = 4/5 (ball reaches 4/5th of previous height)
Stop condition = height < 0.5 meters (50 cm)

Height Calculations:

1. Initial Drop: 1.5 meters

2. First Bounce:
Height = 1.5 × 4/5 = 1.2 meters

3. Second Bounce:
Height = 1.2 × 4/5 = 0.96 meters

4. Third Bounce:
Height = 0.96 × 4/5 = 0.768 meters

5. Fourth Bounce:
Height = 0.768 × 4/5 = 0.6144 meters

6. Fifth Bounce:
Height = 0.6144 × 4/5 = 0.49152 meters
(This is less than 50 cm, so ball stops)

Result:
– Ball hits ground 5 times before stopping
– Final height (0.49152 m) is below stopping condition (0.5 m)
– Answer: 5 bounces

Q. A boy plays with a ball, and he drops if from a height of 1.5 m. Read More »

Q. A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks?

Q. A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks?

(a) 2
(b) 3
(c) 4
(d) 5
Correct Answer: (b) 3

Question from UPSC Prelims 2021 CSAT Paper

Explanation : 

A student appeared in 6 papers

– Total marks per subject = 100
– Total subjects = 6
– Total possible marks = 600
– Overall score = 60% = 360 marks
– Marks distribution pattern: 5x, 6x, 7x, 8x, 9x, 10x

Step 1: Form equation
5x + 6x + 7x + 8x + 9x + 10x = 360
45x = 360

Step 2: Solve for x
x = 360/45 = 8

Step 3: Calculate marks in each subject
Subject 1: 5x = 5 × 8 = 40 marks
Subject 2: 6x = 6 × 8 = 48 marks
Subject 3: 7x = 7 × 8 = 56 marks
Subject 4: 8x = 8 × 8 = 64 marks
Subject 5: 9x = 9 × 8 = 72 marks
Subject 6: 10x = 10 × 8 = 80 marks

Step 4: Count subjects below 60%
60% of 100 = 60 marks
Subjects below 60 marks:
1. 40 marks
2. 48 marks
3. 56 marks

Therefore: Student scored less than 60% in 3 subjects.

Students Paper Scores Analysis

Q. A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks? Read More »

Q. There are two Classes A and B having 25 and 30 students respectively. In Class-A the highest score is 21 and lowest score is 17. In Class-B the highest score is 30 and lowest score is 22. Four students are shifted from Class-A to Class-B.

Q. There are two Classes A and B having 25 and 30 students respectively. In Class-A the highest score is 21 and lowest score is 17. In Class-B the highest score is 30 and lowest score is 22. Four students are shifted from Class-A to Class-B.

Consider the following statements:
1. The average score of Class-B will definitely decrease.
2. The average score of Class-A will definitely increase.
Which of the above statements is/are correct?
(a) 1 only
(b) 2 only
(c) Both 1 and 2
(d) Neither 1 nor 2
Correct Answer: (a) 1 only

Question from UPSC Prelims 2021 CSAT Paper

Explanation :

There are two classes a and b

Class A (Initial):
– Total students: 25
– Highest score: 21
– Lowest score: 17
– Four students will be shifted out

Class B (Initial):
– Total students: 30
– Highest score: 30
– Lowest score: 22
– Will receive four students from Class A

Analysis:

1. Effect on Class B’s Average:
– Initial students: 30
– New total: 34 students
– All incoming students have scores ≤ 21
– All original students have scores ≥ 22
– Therefore, adding any four students from Class A will definitely lower Class B’s average

2. Effect on Class A’s Average:
– Initial students: 25
– New total: 21 students
– Cannot determine if average will increase because:

  • If highest scoring students (around 21) are shifted out → average will decrease
  • If lowest scoring students (around 17) are shifted out → average will increase
  • Without knowing which students are shifted, change in average is uncertain

Conclusion:
– Class B’s average will definitely decrease
– Class A’s average could increase or decrease depending on which students are shifted

Q. There are two Classes A and B having 25 and 30 students respectively. In Class-A the highest score is 21 and lowest score is 17. In Class-B the highest score is 30 and lowest score is 22. Four students are shifted from Class-A to Class-B. Read More »