CSAT 2020

Q. Let XYZ be a three-digit number, where (x + y + z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

(a) 3
(b) 9
(c) 37
(d) (X + Y + Z)

Correct Answer: (b) 9

Question from UPSC Prelims 2020 CSAT Paper

Model Answer:

Let XYZ be a 3 digit number

Let’s write XYZ in expanded form, where X, Y, and Z are the digits in the hundreds, tens, and units places, respectively.

XYZ = 100X + 10Y + Z

Similarly, we can write YZX and ZXY in expanded form:

YZX = 100Y + 10Z + X
ZXY = 100Z + 10X + Y

Adding these three expressions, we get:

XYZ + YZX + ZXY = 100X + 10Y + Z + 100Y + 10Z + X + 100Z + 10X + Y
= 111X + 111Y + 111Z=111(X + Y + Z)

Factors of 111 are 3 and 37. That eliminate option 3 and 37.

xyz be a 3 digit number

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