BPSC PT 70

Q. What is the 14th term of the sequence 14, 10, 6, 2,….. ?

a) – 42
b) – 34
c) – 46
d) – 38

Question from BPSC PT 70, 2024

The correct answer is: d) -38

Explanation:

Let’s solve this step by step:

1) First, let’s identify the pattern in the sequence
14, 10, 6, 2, …

2) Looking at consecutive terms:
14 → 10 (decrease by 4)
10 → 6 (decrease by 4)
6 → 2 (decrease by 4)

3) This is an arithmetic sequence with a common difference of -4

4) To find the 14th term, we can use the arithmetic sequence formula:
an = a₁ + (n-1)d
where:
a₁ = first term = 14
d = common difference = -4
n = position we want = 14

5) Plugging into the formula:
a₁₄ = 14 + (14-1)(-4)
= 14 + (13)(-4)
= 14 + (-52)
= -38

The answer is d) -38

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