CSAT 2020

Q. What is the remainder when 51 x 27 x 35 x 62 x 75 is divided by 100? 

Q. What is the remainder when 51 x 27 x 35 x 62 x 75 is divided by 100?

(a) 50
(b) 25
(c) 5
(d) 1
Correct Answer: (a) 50

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

Remainder when 51*27*35*62*75 divided by 100

To find remainder when divided by 100:
Take ones place digit of each number: 1, 7, 5, 2, 5
Multiply them: 1 × 7 × 5 × 2 × 5 = 350
Find remainder when 350 ÷ 100 = 50 (remainder)

Therefore, when 51 × 27 × 35 × 62 × 75 is divided by 100, the remainder is 50.

Answer: (a) 50

Q. What is the remainder when 51 x 27 x 35 x 62 x 75 is divided by 100?  Read More »

Q. What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case?

Q. What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case?

(a) 1012
(b) 1022
(c) 1122
(d) 1222
Correct Answer: (b) 1022

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

Let’s solve this problem step by step:

Finding the least four-digit number with remainder 2 when divided by 3, 4, 5, and 6

STEP 1: Find the LCM of 3, 4, 5, and 6
– First, we need the least common multiple (LCM) of 3, 4, 5, and 6
– The LCM of these numbers is 60

STEP 2: Find the smallest four-digit number divisible by LCM
– We need to find the smallest four-digit number divisible by 60
– The smallest four-digit number divisible by 60 is 1020

STEP 3: Add remainder
– Since we want remainder 2 when divided by 3, 4, 5, and 6
– We add 2 to our number: 1020 + 2 = 1022

ANSWER: 1022 is the least four-digit number that leaves remainder 2 when divided by 3, 4, 5, and 6

VERIFICATION:
1022 ÷ 3 = 340 remainder 2
1022 ÷ 4 = 255 remainder 2
1022 ÷ 5 = 204 remainder 2
1022 ÷ 6 = 170 remainder 2

Q. What is the least four-digit number when divided by 3, 4, 5 and 6 leaves a remainder 2 in each case? Read More »

Q. The recurring decimal representation 1.272727… is equivalent to 

Q. The recurring decimal representation 1.272727… is equivalent to

(a) 13/11
(b) 14/11
(c) 127/99
(d) 137/99
Correct Answer: (b) 14/11

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

Recurring Decimal 1.272727…

To solve this problem, let x = 1.272727…

Then, 100x = 127.272727…

Subtracting x from 100x, we get:

  • 99x = 126
  • x = 126/99

We can simplify this fraction by dividing the numerator and denominator by their greatest common factor, which is 3:

x = (126/3)/(99/3) = 42/33

We can simplify this fraction further by dividing the numerator and denominator by their greatest common factor, which is 3:

x = (42/3)/(33/3) = 14/11

Therefore, the recurring decimal representation 1.272727… is equivalent to 14/11, and the correct answer is (b).

Q. The recurring decimal representation 1.272727… is equivalent to  Read More »

Q. Consider the following data: For which period was the natural growth rate maximum? 

Q. Consider the following data: For which period was the natural growth rate maximum?

Year : Birth rate – Death rate
1911-1921 : 48.1 – 35.5
1921-1931 : 46.4 – 36.3
1931-1941 : 45.2 – 31.2
1941-1951 : 39.9 – 27.4
1951-1961 : 41.7 – 22.8
1961-1971 : 41.1 – 18.9
1971-1981 : 37.1 – 14.8

(a) 1911 – 1921
(b) 1941-1951
(c) 1961 – 1971
(d) 1971-1981
Correct Answer: (d) 1971-1981

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

For which period was the natural growth rate maximum ?

The natural growth rate is calculated by subtracting the death rate from the birth rate. From the data you provided, we can calculate the natural growth rates for each period:

  • 1911-1921: 48.1 – 35.5 = 12.6
  • 1921-1931: 46.4 – 36.3 = 10.1
  • 1931-1941: 45.2 – 31.2 = 14
  • 1941-1951: 39.9 – 27.4 = 12.5
  • 1951-1961: 41.7 – 22.8 = 18.9
  • 1961-1971: 41.1 – 18.9 = 22.2
  • 1971-1981: 37.1 -14 .8 = 22.3

The maximum natural growth rate was 22.3 during the period 1971-1981.

Q. Consider the following data: For which period was the natural growth rate maximum?  Read More »

Q. What is the largest number among the following? 

Q. What is the largest number among the following? 

(a) (1/2)^-6
(b) (1/4)^-3
(c) (1/3)^-4
(d) (1/6)^-2
Correct Answer: (c) (1/3)^-4

Question from UPSC Prelims 2020 CSAT Paper

Explanation : 

Largest Number

Let’s solve this problem step by step. A negative exponent means that the base is inverted and the exponent becomes positive. For example, (1/2)^-6 can be written as (2/1)^6.

Using this logic, we can rewrite all the options as follows:
(a) (1/2)^-6 = (2/1)^6 = 64
(b) (1/4)^-3 = (4/1)^3 = 64
(c) (1/3)^-4 = (3/1)^4 = 81
(d) (1/6)^-2 = (6/1)^2 = 36

So among these options, the largest number is 81.

So (c) (1/3)^-4 is indeed the correct answer.

Q. What is the largest number among the following?  Read More »

Q. A shop owner offers the following discount options on an article to a customer:

Q. A shop owner offers the following discount options on an article to a customer:

1. Successive discounts or 10% and 20%, and then pay a service tax of 10%
2. Successive discounts of 20% and 10%, and then pay a service tax of 10%
3. Pay a service tax or 10% first, then successive discounts of 20% and 10%

Which one of the following is correct?
(a) 1 only is the best option for the customer.
(b) 2 only is the best option for the customer.
(c) 3 only is the best option for the customer.
(d) All the options are equally good for the customer.
Correct Answer: (d) All the options are equally good for the customer.

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

A shop owner offers the following …

Let’s calculate the effective discount for each option, assuming the original price of the article is P.

Option 1:

First discount: 10% -> P * (1 – 0.10) = 0.9P
Second discount: 20% -> 0.9P * (1 – 0.20) = 0.9P * 0.8 = 0.72P
Service tax: 10% -> 0.72P * (1 + 0.10) = 0.72P * 1.1 = 0.792P

Option 2:

First discount: 20% -> P * (1 – 0.20) = 0.8P
Second discount: 10% -> 0.8P * (1 – 0.10) = 0.8P * 0.9 = 0.72P
Service tax: 10% -> 0.72P * (1 + 0.10) = 0.72P * 1.1 = 0.792P

Option 3:

Service tax: 10% -> P * (1 + 0.10) = 1.1P
First discount: 20% -> 1.1P * (1 – 0.20) = 1.1P * 0.8 = 0.88P
Second discount: 10% -> 0.88P * (1 – 0.10) = 0.88P * 0.9 = 0.792P

All three options result in the customer paying the same final price, which is 79.2% of the original price (0.792P). So, all options are equivalent in terms of the final price for the customer.

Q. A shop owner offers the following discount options on an article to a customer: Read More »

Q. A simple mathematical operation in each number of the sequence 14, 18, 20, 24, 30, 32, results in a sequence with respect to prime numbers. Which one of the following is the next number in the sequence? 

Q. A simple mathematical operation in each number of the sequence 14, 18, 20, 24, 30, 32, results in a sequence with respect to prime numbers. Which one of the following is the next number in the sequence?

(a) 34
(b) 36
(c) 38
(d) 40
Correct Answer: (c) 38

Question from UPSC Prelims 2020 CSAT Paper

Explanation : 

A simple mathematical operation

If we subtract 1 from each number in the original sequence, we get the following sequence:

13, 17, 19, 23, 29, 31

Notice that this is simply the sequence of prime numbers starting from 13.

The next prime number after 31 is 37. Therefore, the next number in the original sequence, which corresponds to the prime number 37 after subtracting 1, is:

37 + 1 = 38

Therefore, the correct answer is (c) 38

Q. A simple mathematical operation in each number of the sequence 14, 18, 20, 24, 30, 32, results in a sequence with respect to prime numbers. Which one of the following is the next number in the sequence?  Read More »

Q. In the sum ⊗ + 1 ⊗ + 5 ⊗ + ⊗ ⊗ + ⊗ 1 = 1 ⊗ ⊗  for which digit does the symbol ⊗ stand?

Q. In the sum ⊗ + 1 ⊗ + 5 ⊗ + ⊗ ⊗ + ⊗ 1 = 1 ⊗ ⊗  for which digit does the symbol ⊗ stand?

(a) 2
(b) 3
(c) 4
(d) 5
Correct Answer: (b) 3

Question from UPSC Prelims 2020 CSAT Paper

Explanation :

x+1x+5x+xx+x1=1xx

x + 1x + 5x + xx + x1 = 1xx

=> x + 10+ x + 50 + x +10x + x + 10x + 1 = 100 + 10x + x

=> 24x + 61 = 100 + 11x

=> 13x = 39

=> x = 3

Q. In the sum ⊗ + 1 ⊗ + 5 ⊗ + ⊗ ⊗ + ⊗ 1 = 1 ⊗ ⊗  for which digit does the symbol ⊗ stand? Read More »

Q. Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

Q. Let XYZ be a three-digit number, where (x + y + z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

(a) 3
(b) 9
(c) 37
(d) (X + Y + Z)

Correct Answer: (b) 9

Question from UPSC Prelims 2020 CSAT Paper

Model Answer:

Let XYZ be a 3 digit number

Let’s write XYZ in expanded form, where X, Y, and Z are the digits in the hundreds, tens, and units places, respectively.

XYZ = 100X + 10Y + Z

Similarly, we can write YZX and ZXY in expanded form:

YZX = 100Y + 10Z + X
ZXY = 100Z + 10X + Y

Adding these three expressions, we get:

XYZ + YZX + ZXY = 100X + 10Y + Z + 100Y + 10Z + X + 100Z + 10X + Y
= 111X + 111Y + 111Z=111(X + Y + Z)

Factors of 111 are 3 and 37. That eliminate option 3 and 37.

xyz be a 3 digit number

Q. Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by Read More »

Q. Let x, y be the volumes; m, n be the masses of two metallic cubes P and Q respectively. Each side of Q is two times that of P and mass of Q is two times that of P.

Q. Let x, y be the volumes; m, n be the masses of two metallic cubes P and Q respectively. Each side of Q is two times that of P and mass of Q is two times that of P.

Let u =m/x and V=n/y. which one or the following is correct?
(a) u = 4v
(b) u = 2v
(c) v=u
(d) v = 4u
Correct Answer: (a) u = 4v

Question from UPSC Prelims 2020 CSAT Paper

Explanation : 

Let x y be the volumes …

Let’s solve this step by step.

1) Let’s say the side length of cube P is ‘a’
Then volume of P (x) = a³
Mass of P is m

2) For cube Q:
Side length is 2a (given: each side of Q is two times that of P)
Volume of Q (y) = (2a)³ = 8a³
Mass of Q (n) = 2m (given: mass of Q is two times that of P)

3) Now, let’s calculate u = m/x
u = m/a³

4) Let’s calculate v = n/y
v = 2m/(8a³)
v = (2m)/(8a³)
v = m/(4a³)
v = (m/a³)/4
v = u/4

5) Therefore:
u = 4v

Looking at the options, (a) u = 4v is correct.

The answer is (a).

Q. Let x, y be the volumes; m, n be the masses of two metallic cubes P and Q respectively. Each side of Q is two times that of P and mass of Q is two times that of P. Read More »