Explanation : 

Cuboid Painting and Cubes Separation

The given cuboid is of dimensions 7 cm x 5 cm x 3 cm.

1. The small cubes with no paint on any face will be the ones that are not on the surface of the cuboid. These will be the cubes that are in the interior of the cuboid. The interior of the cuboid will have dimensions (7-2) cm x (5-2) cm x (3-2) cm = 5 cm x 3 cm x 1 cm = 15 cubes. So, the first statement is correct.

2. The small cubes with exactly two faces painted will be the ones that are on the edges of the cuboid but not at the corners. These will be painted with the colors of the two faces that meet at that edge. The edges with blue and green paint are of length 5 cm and 3 cm. But the corners of these edges will not have exactly two faces painted. So, we subtract 2 from each edge length to get the number of cubes with exactly two faces painted. This gives us (5-2) + (3-2) = 3 + 1 = 4 cubes. So, the second statement is incorrect.

Therefore, the correct answer is (a) 1 only.

Explanation : 

Let’s analyze each statement:

1. If T is true, then at least one of P and R must be false.

• The contrapositive of 1 is: “If both P and R are true, then T is false”. This statement can be derived from the given statements as follows:
  • If P is true, then Q and S are true (by I).
  • If R and S are true, then T is false (by II).
  • Therefore, if P and R are true, then Q, S and T are false (by transitivity).
• Since the contrapositive of 1 is true, 1 is also true.

2. If Q is true, then P is true.

According to statement I, if P is true, then both Q and S are true. However, this does not imply that if Q is true, then P must be true. It is possible for Q to be true while P is false. Therefore, this statement is false.

So, the correct answer is (a) 1 only.

Explanation : 

The sequence follows the pattern where each group of 4 letters is a permutation of ABCD, where each letter appears once more than it did in the previous group.

In the first group, A appears once, B appears once, C appears once, and D does not appear.

In the second group, A appears twice, B appears twice, C does not appear, and D appears once.

In the third group, A appears once, B appears once, C appears once, and D appears twice.

Following this pattern, in the fourth group, A should appear twice, B should not appear, C should appear once, and D should appear twice.

Therefore, the correct answer is (d) DDCA.

Explanation : 

From the given statement, we can interpret the following:

I. P is not smaller than Q (P≥Q)
II. P is not greater than T (P≤T)
III. T is not smaller than R (T≥R)
IV. R is neither greater nor equal to S (R<S)

Now, let’s analyze the conclusions:

Conclusion-1: Q is neither greater nor equal to T (Q<T). This conclusion does not follow from the statement because we know that P≥Q and P≤T, but we cannot determine the relationship between Q and T.

Conclusion-2: S is not smaller than Q (S≥Q). This conclusion follows from the statement. Since P≥Q, P≤T, T≥R, and R<S, we can infer that S≥Q.

Therefore, only Conclusion-2 follows from the statement. So, the correct answer is (b) Only Conclusion-2 follows from the Statement.

Explanation : 

Minimum Number of Coins to Buy 78 gm

To buy 78 gm of coins, with the largest coin being 50 gm and the smallest coin being 2 gm, we need to find the minimum number of coins required.

If we try to use only one of each coin weight, the sum would be: 50 + 10 + 10 + 2 + 2 + 2 + 2 = 78

So, using one coin of each weight, we need to buy 7 coins to get a total of 78 gm.

To weigh 78 gm using these coins, one can use 5 coins of 50 gm, 25 gm, 10 gm, -5 gm, and -2 gm. This is done by placing the 50 gm, 25 gm, and 10 gm coins on one side of the balance and the -5 gm and -2 gm coins (which are actually 5 gm and 2 gm coins, but placed on the opposite side) on the other side.

Therefore, both statements are correct. The answer is (c) Both 1 and 2.

Explanation : 

Five Children’s Ages Analysis

Let’s consider each statement separately:

Statement-1: The age of the eldest is 3 times the youngest.
Since the ages of the children increase by 2 years successively, let’s denote the age of the youngest child as ‘a’. Then the ages of the other children would be a+2, a+4, a+6, and a+8. According to the statement, the age of the eldest child (a+8) is 3 times the age of the youngest child (a). This gives us the equation 3a = a+8. Solving this equation, we find that a = 4. Therefore, the age of the youngest child is 4 years old.

Statement-2: The average age of the children is 8 years.
The average age is the sum of the ages divided by the number of children. So, 5a+20 = 8*5. Solving this equation, we again find that a = 4. Therefore, the age of the youngest child is 4 years old.

In conclusion, each statement alone is enough to answer the question. Therefore, the correct answer is (b) The Question can be answered by using either Statement alone.

Explanation : 

Given Information:

75 persons took tea.
60 persons took coffee.
15 persons took both tea and coffee.

Analysis of the Given Information:
The number of persons who took only tea = 75 – 15 = 60.
The number of persons who took only coffee = 60 – 15 = 45.
So, the total number of persons who took tea or coffee = 60 (only tea) + 45 (only coffee) + 15 (both) = 120.

Statement-1: 50 persons took milk.

Since it’s given that no one taking milk takes tea, these 50 persons are distinct from the 120 persons who took tea or coffee.
However, this statement doesn’t provide the total number of persons attending the party since we don’t know if these 50 persons include those who took coffee, tea, or both.

Statement-2: Number of persons who attended the party is five times the number of persons who took milk only.

Let y be the number of persons who took only milk.
The total number of persons attending the party would then be 120 (those who took tea or coffee) + y.
According to the statement, this total is 5 times the number of persons who took only milk, which gives us the equation: 120 + y = 5y.
Solving this equation: 120 = 5y – y, 120 = 4y, y = 120 / 4, y = 30.
Therefore, the total number of persons attending the party is 120 + 30 = 150.

Conclusion:

Statement-1 alone is not sufficient to answer the question.
Statement-2 alone is sufficient to answer the question.

Explanation : 

Sequence of Passing the Ring

The ring is passed in the following sequence: 1, 2, 4, 7, 11, 16, 22, 29, 37, 6, 16, 27, 39, 12, 26, 1.

This sequence is formed by adding 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 to the position of the child respectively and taking modulo 40 (since there are 40 children in the circle).

For example, the ring is initially with child-1. We add 1 to it and get 2. So, the ring is passed to child-2. Then we add 2 to 2 and get 4. So, the ring is passed to child-4. And so on.

When we add 15 to 26, we get 41. But since there are only 40 children, we take modulo 40 to get 1. So, the ring is passed back to child-1.

Therefore, the ring is back with child-1 after 15 changes. Hence, the correct answer is (b) 15.

Explanation : 

Synchronization of Traffic Signals

The time taken by each signal to complete a full cycle (green to red and back to green) is twice the time taken to change from green to red. So, the first signal takes 50 seconds, the second signal takes 78 seconds, and the third signal takes 120 seconds to complete a full cycle.

To find out when all three signals will be green simultaneously again, we need to find the least common multiple (LCM) of these three times.

The LCM of 50, 78, and 120 is 7800 seconds.

7800 seconds is equivalent to 2 hours and 10 minutes.

So, if all three signals were green at 2:00 p.m., they will all be green simultaneously again at 4:10 p.m.

Therefore, the correct answer is (b) 4:10 p.m.

Explanation : 

10 Consecutive Selections in a Circle

When you select 10 out of 12 things in a circle, you are actually selecting a starting point and then counting the next 9 things in the clockwise direction.

Since there are 12 things in the circle, there are 12 possible starting points. Therefore, there are 12 different ways to select 10 consecutive things out of 12 things in a circle taken in the clockwise direction.