Q. What is the smallest number greater than 1000 that when divided by any one of the numbers 6, 9. 12, 15, 18 leaves a remainder of 3?
a. 1063
b. 1073
c. 1083
d. 1183
Correct Answer: c. 1083
Question from UPSC Prelims 2022 CSAT Paper
Explanation :
Finding the smallest number greater than 1000 with specific conditions.
LCM of 6, 9, 12, 15 and 18 = 180
Smallest number greater than 1000 which is a multiple of 180 is 1080.
So, Required number = 1080 + 3 = 1083
