CSAT 2022

Q. What is the smallest number greater than 1000 that when divided by any one of the numbers 6, 9. 12, 15, 18 leaves a remainder of 3?

a. 1063
b. 1073
c. 1083
d. 1183
Correct Answer: c. 1083

Question from UPSC Prelims 2022 CSAT Paper

Explanation : 

Finding the smallest number greater than 1000 with specific conditions.

LCM of 6, 9, 12, 15 and 18 = 180
Smallest number greater than 1000 which is a multiple of 180 is 1080.

So, Required number = 1080 + 3 = 1083

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